C# Method Overloading

Method Overloading

With method overloading, multiple methods can have the same name with different parameters:

int MyMethod(int x)
float MyMethod(float x)
double MyMethod(double x, double y)

Consider the following example, which have two methods that add numbers of different type:

static int PlusMethodInt(int x, int y)
{
  return x + y;
}

static double PlusMethodDouble(double x, double y)
{
  return x + y;
}

static void Main(string[] args)
{
  int myNum1 = PlusMethodInt(8, 5);
  double myNum2 = PlusMethodDouble(4.3, 6.26);
  Console.WriteLine("Int: " + myNum1);
  Console.WriteLine("Double: " + myNum2);
}

Instead of defining two methods that should do the same thing, it is better to overload one.

In the example below, we overload the PlusMethod method to work for both int and double:

static int PlusMethod(int x, int y)
{
  return x + y;
}

static double PlusMethod(double x, double y)
{
  return x + y;
}

static void Main(string[] args)
{
  int myNum1 = PlusMethod(8, 5);
  double myNum2 = PlusMethod(4.3, 6.26);
  Console.WriteLine("Int: " + myNum1);
  Console.WriteLine("Double: " + myNum2);
}